given the 1x5 vector x, y must be the square of the horizontal concatenation of the third and fifth elements. So, if x = [1 1 1 1 1], y must be [1 1].
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2 Comments
Matthew Eicholtz
on 7 Feb 2015
The example you give in the problem statement is not very demonstrative.
J.R.! Menzinger
on 2 Mar 2015
HAHAHAHA Matt: this was great!!!
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