Consider the recursion relation:
x_n = (x_(n-1)*x_(n-2))^k
Given x_1, x_2, and k, x_n can be found by this definition. Write a function which takes as input arguments x_1, x_2, n and k. The output should be x_n.
For example, if x_1=exp(1), x_2=pi, n=5, and k=5/9 then:
R = get_recurse(exp(1),pi,5,4/9)
R =
2.31187497992966
Solution Stats
Problem Comments
4 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers84
Suggested Problems
-
Back to basics 13 - Input variables
385 Solvers
-
939 Solvers
-
261 Solvers
-
764 Solvers
-
find the maximum element of the matrix
538 Solvers
More from this Author6
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
is there a story as to why this is "infernal"?
I hate recursion, so it is all infernal to me! Iteration is the way to go...
Test suite could helpfully include n=1 and n=2 tests. I thought that it needed extra complexity to handle these, but @bmtran's top solution shows it doesn't.
I spend a lot of time to get the correct R from the example. The issue is that you say k = 5/9 instead of 4/9 . Just a typo to correct . Thanks