Inputs:
- f: cell-array of function handles
- x: column vector of x values
- y: column vector of y values, same length as x
Output:
- a: column vector of coefficients, same length as f
In a correct answer the coefficients a take values such that the function
fit = @(x) a(1)*f{1}(x) + a(2)*f{2}(x) + a(3)*f{3}(x) +...+ a(end)*f{end}(x)minimizes the sum of the squared deviations between fit(x) and y, i.e. sum((fit(x)-y).^2) is minimal.
Remarks:
- The functions will all be vectorized, so e.g. f{1}(x) will return results for the whole vector x
- The absolute errors of a must be smaller than 1e-6 to pass the tests
Solution Stats
Problem Comments
6 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers157
Suggested Problems
-
Make the vector [1 2 3 4 5 6 7 8 9 10]
52863 Solvers
-
2599 Solvers
-
5972 Solvers
-
465 Solvers
-
Converts numbers into characters
2039 Solvers
More from this Author7
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
your functions are not all truly 'vectorized'; I would change @(x)1 to @(x)ones(size(x)) for a more consistent 'vectorized' behavior...
Yup, you're right. I made the adjustment...
not meaning to be picky, but in the third test you might want to use aref.' instead of aref' (if x take negative values, which occurs at random for this test, then log(x) takes complex values, and the aref' portion takes the conjugate of the complex valued results); perhaps it is simpler to make sure x takes only positive values...
and nice problem, by the way!
Thanks! Nice catch, I fixed that second issue too (those randomized tests have their drawbacks)
Sorry, but I can not understand the problem to solve.
Can anyone explain to me, please?