Problem 252. Project Euler: Problem 16, Sums of Digits of Powers of Two

Created by @bmtran (Bryant Tran)

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2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.

What is the sum of the digits of the number 2^N?

Thanks to Project Euler Problem 16.

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Last solution submitted on Sep 12, 2019

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@bmtran (Bryant Tran) on 4 Feb 2012

added a test case to make it a wee bit harder

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Solution 216618

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Harish Maradana on 13 Mar 2013

function y = pow2_sumofdigits(x)
number = sym(2^x);
n = char(number);
y = 0;
for i = 1:length(n)
y = y + str2double(n(i));
end
end
this code gives exact results on my mechine but not work in cody show error
Error: License checkout failed.
License Manager Error -5
Cannot find a license for Symbolic_Toolbox.
Troubleshoot this issue by visiting:
http://www.mathworks.com/support/lme/R2013a/5
Diagnostic Information:
Feature: Symbolic_Toolbox
License path: 13501@10.206.97.41:13501@10.10.207.33:/tmp/matlabpref/.matlab/R2013a_licenses:/opt/mlsedu/matlab/R2013a/licenses/license.dat:/opt/mlsedu/matlab/R2013a/licenses
Licensing error: -5,0.

please help me ...........

Problem 252. Project Euler: Problem 16, Sums of Digits of Powers of Two

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Problem 252. Project Euler: Problem 16, Sums of Digits of Powers of Two

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