Problem 240. Project Euler: Problem 6, Natural numbers, squares and sums.

Created by Doug Hull

Solve Later

The sum of the squares of the first ten natural numbers is,

1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first N (where N is the input) natural numbers and the square of the sum.

Thank you to Project Euler Problem 6

Solve

Solution Stats

4279 Solutions
2326 Solvers

Last Solution submitted on Apr 16, 2025

Last 200 Solutions

Problem Comments

2 Comments

2 Comments

John D'Errico on 28 Aug 2016

A problem where one must be at least a little careful about floating point arithmetic. It might have been interesting if one of the test cases were x=1e5 or larger. Even more interesting if the execution time were a factor in the "score". These factors might impact how the problem would be best solved.

Srishti Saha on 13 Oct 2018

@ Doug Hall, I have solved all the problems in the series. However, I have not received the badge and the associated scores on completion of the series. Can you please look into this?

Solution Comments

Show comments

Problem Recent Solvers2326

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Problem 240. Project Euler: Problem 6, Natural numbers, squares and sums.

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers2326

Suggested Problems

More from this Author51

Problem Tags

Community Treasure Hunt

Problem 240. Project Euler: Problem 6, Natural numbers, squares and sums.

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers2326

Suggested Problems

More from this Author51

Problem Tags

Community Treasure Hunt

Players