Problem 2397. Leap Year
According to Gregorian Calender(which is in use now, in many countries),decide whether a given year is a leap year or not. Give 'true' if the given year is a leap year and 'false',if not.
Note: In the Gregorian calendar 3 criteria must be taken into account to identify leap years:
The year is evenly divisible by 4; If the year can be evenly divided by 100, it is NOT a leap year, unless; The year is also evenly divisible by 400. Then it is a leap year.
Solution Stats
Problem Comments
-
3 Comments
Kumar, in problem #4 there is one to many right parenthesis. George...
Actually I just realized it is the "isequal" is missing in test #4.
Thanks George.Am extremely sorry for that.I just corrected it.
Solution Comments
Show commentsProblem Recent Solvers183
Suggested Problems
-
The Goldbach Conjecture, Part 2
2383 Solvers
-
Is my wife right? Now with even more wrong husband
1334 Solvers
-
800 Solvers
-
Add a row of zeros on top of a matrix
258 Solvers
-
1470 Solvers
More from this Author1
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!