Problem 231. Differential equations I

Created by Tomasz

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Given a function handle f an initial condition y0 and a final time tf, solve numerically the differential equation

dy/dt = f(y)

for the function y(t) between t=0 and t=tf. Give as a result res=y(tf).

Example:

   f = @(x) -x;
   tf= 1;
   y0= 1;

 => y(tf) = 1/e = 0.367879441171442

Remarks: aim at a relative precision of around 1e-6. The function is analytic in the interval [0,1].

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Last Solution submitted on Sep 10, 2024

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Nikolaos Nikolaou on 24 Feb 2021

last test needs a fix

goc3 on 25 Feb 2021

@Nikolaos Nikolaou: the reference solution provided by the author passes the test suite, as do many community solutions. Can you clarify your comment?

warnerchang on 7 Aug 2023

As Nikolaos mentioned, the last test needs a fix. The value of 'a' is not transferred into the function handle 'f', and 'a' is just a char (not a value) in 'f'.

Christian Schröder on 7 Aug 2023

The last test case is not broken. When you define an anonymous function that includes variables, those variables are stored along with the function and remain available to it. This is true also when handles to the anonymous function are passed around, or when the variables in question are cleared from memory. See https://www.mathworks.com/help/matlab/matlab_prog/anonymous-functions.html#f4-71621 .

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Problem 231. Differential equations I

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