Problem 2073. Split a given string from the first instance of a given character

Created by Mehmet E. Yavuz

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?><w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>A simple operation to split a given string into two substrings at the point where the desired character is first found. e.g.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/><w:jc w:val=\"left\"/></w:pPr><w:r><w:t>inputString: 'we have 6 cars' split it from '6'</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/><w:jc w:val=\"left\"/></w:pPr><w:r><w:t>output: 'we have ' and '6 cars'</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/><w:jc w:val=\"left\"/></w:pPr><w:r><w:t>If the desired character is not found then first substring is same as the whole string and the second string is empty string, i.e. y2='';</w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

Solve

Solution Stats

186 Solutions
80 Solvers

Last Solution submitted on Sep 13, 2022

Last 200 Solutions

Problem Comments

3 Comments

3 Comments

Marcel on 6 Jan 2014

how about adding some test cases with multiple occurances of the divider?

Mehmet E. Yavuz on 7 Jan 2014

Thanks, good idea

goc3 on 31 May 2017

Additional test cases have been added.

Solution Comments

Solution 1214787

1 Comment

1 Comment

Dyuman Joshi on 30 Dec 2020

Another new command I learned recently!

Problem Recent Solvers80

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!