among a,b,c., specify the hypotenuse.
that's the tricky part here ;) Check all combinations - too bad 'combvec' doesnt work here
Passes for True, but Failing when I get to false test?? Not sure at the moment what I could be missing.
A great example!
Yes, I finally got it
The 2nd test is incorrect.
function flag = isRightAngled(a,b,c)
x=[a b c];
flag = y(1)^2+y(2)^2==y(3)^2;
flag = false;
A = (acos((b^2+c^2-a^2)/(2*b*c)))*180/pi;
B = (acos((a^2+c^2-b^2)/(2*a*c)))*180/pi;
flag = true;
why is it correct? only because the test case.
a=100, b=20, c=5 will flag true but it not true
Without using str2num or regexp
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