Tanya, you like triangles.
These are interesting
a = sqrt(c^2-b^2);
this isn't a calculation!
test_1 a=sqrt(3) is longer than b=1
the good solution would be
a= min(sqrt(c^2 -b^2),b)
Kudos for finding this solution - it did indeed meet all the test cases, but wasn't quite what I had in mind! I will add a new test.
Getting logical indexes
Vectorize the digits of an Integer
Find the maximum number of decimal places in a set of numbers
04 - Scalar Equations 1
Area of a triangle
Dimensions of a rectangle
Is this triangle right-angled?
Side of an equilateral triangle
Length of the hypotenuse
Side of a rhombus
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