You should mention that the answer should be given as a column vector, rather than row vector.
One at this time must examine the assessment code to give the right answer, while I think it should be self-contained in the question itself.
Thanks Richard. I have modified the problem description to mention this.
can anyone tell me the flaw in this code (im still very new to MATLAB)
function good = find_good_hotels(hotels,ratings,cutoff)
for c = 1:10 //the number 10 is a random number
if ratings(c) > cutoff | ratings(c) == cutoff
good = hotels(c);
else x = "not a good hotel"
@Kanishka, the question does not mention to return "not a good hotel", it only asks to return the names of hotels whose ratings is equalto or more than the threshold.
very good and challenging problem
Can I know how can we solve this with size 12?
I just can't reduce my answer's size to the smallest ones xD
It should be mentioned in the problem that hotels and ratings are column vectors.
good = hotels(ratings >= cutoff)';
failed because I (imho correctly) assumed that a list is a row vector.
how is the size of a solution calculated?
These solutions with a regexp seem to be designed to get this count low but imho are not the best solutions and should not be allowed as leading solutions. It is more of a keep the size low trick.
Helemaal mee eens Jorden.
The problem is incorrectly defined. The solver doesn't know if "hotel" is a row or column vector in the first place and I am not sure you can use logical signs for strings, that doesn't make sense to me (ie. where is it defined that string "good" is logically greater than "not good").
The leading solution is super concise. I learned something from it.
I don't understand how this solution works? The return value is not set?
return only the names of those hotels with a rating of cutoff value or above in an output variable good.
So this solution will fail if rating is equal to cutoff. This is not tested in the asserts!
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