How to convert the digits of a number in a higher number base to an array
조회 수: 2 (최근 30일)
이전 댓글 표시
I converted 32 to base 18 using the code
A=dec2base(32,18)
and the output was
'1B'
I want to convert the digits of 1B to an array [1 B]. so i used the code
num2str(A)-'0'
Which gave me an output
ans =
1 21
Instead of ans= 1 B. Please help.
댓글 수: 8
dpb
2021년 8월 2일
편집: dpb
2021년 8월 2일
Newer releases of Matlab do support hexadecimal notation, but otherwise, only base 10 numbers are allowed outside of text datatypes." @Rik
While not really pertinent to the discussion, Forth has the system constant BASE that lets one define the base dynamically...
BINARY
...everything here in base 2
DECIMAL
...now we're back in base 10
that is extremely handy and that I miss.
: DECIMAL 10 BASE ! ;
: HEX 16 BASE ! ;
: OCTAL 8 BASE ! ;
: BINARY 2 BASE ! ;
are the common defining words. Of course, one needs be certain DECIMAL is in effect when defining the above!!! :)
Just a sidebar into days of yore..."we now return you to your regular programming".
답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Characters and Strings에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!