# Fill array between values

조회 수: 4(최근 30일)
J PARK 2021년 7월 28일
댓글: J PARK 2021년 7월 28일
I have an array like this.
0 0 0 0 0 0 1 0 0 0 0 0 2 0 0 0 0 0 0 0
0 0 0 0 0 1 0 0 1 0 0 2 0 2 0 0 0 0 0 0
0 0 0 0 0 0 1 0 2 0 1 0 2 0 0 0 0 0 0 0
I'd like to fill 3 between 1 and 2, like this.
0 0 0 0 0 0 1 3 3 3 3 3 2 0 0 0 0 0 0 0
0 0 0 0 0 1 3 3 1 3 3 2 3 2 0 0 0 0 0 0
0 0 0 0 0 0 1 3 2 0 1 3 2 0 0 0 0 0 0 0
Is there any way to solve this?
I can't find function to do so.

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### 채택된 답변

Chunru 2021년 7월 28일
The rule is not clear in your question. In first/second row, you fill 3 between first 1 and last 2. In third row, you fille 3 between 2 pairs of 1 and 2.
The code below assume the rule is to fill 3 between 1st 1 and last 2. You can change the code to fit the rule you set.
A =[0 0 0 0 0 0 1 0 0 0 0 0 2 0 0 0 0 0 0 0
0 0 0 0 0 1 0 0 1 0 0 2 0 2 0 0 0 0 0 0
0 0 0 0 0 0 1 0 2 0 1 0 2 0 0 0 0 0 0 0];
for i=1:size(A,1)
i1 = find(A(i,:)==1, 1, 'first');
i2 = find(A(i,:)==2, 1, 'last');
i0 = find(A(i,i1:i2) == 0);
A(i, i1-1 + i0) = 3;
end
A
A = 3×20
0 0 0 0 0 0 1 3 3 3 3 3 2 0 0 0 0 0 0 0 0 0 0 0 0 1 3 3 1 3 3 2 3 2 0 0 0 0 0 0 0 0 0 0 0 0 1 3 2 3 1 3 2 0 0 0 0 0 0 0
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J PARK 2021년 7월 28일
Umm..
If 1 or 2 duplicates, I want to use first 1 and last 2.

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R2021a

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