How to create a structure array?
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I would like to associate to every name on the left an array with all the numbers on the right column associated to that name. Idk if this would be the best way of dividing the data according to the names, if you have other ideas I'm also open to new solutions
"NovanaModelTUDEAA" 19907
"NovanaModelB8" 0
"DK2013Hulbyrenden" 2456.9
"NovanaModelB53" 2000
"DKQNPAa62110222" 1349.5
"NovanaModelLINDESAADK1" 97
"DK20134780780" 0
"NovanaModelB18" 1469.5
"NovanaModelB28" 7581
"NovanaModelB18" 979.67
"DK2013Svenstruprenden" 2282
"NovanaModelB18" 1469.5
"NovanaModelB28" 2940
"NovanaModelTRYGGEVAELDEAA" 12481
"NovanaModelSKVL9" 617
"NOVANAMODELLERKENFELDAA" 29066
"NOVANAMODELVOLDBAEK" 4225
"NOVANAMODELLYNGBYGAARDSAA" 16316
"NOVANAMODELMODEBROBAEK" 4100
"DK20132255838" 0
"DK20132255838" 489.83
"NovanaModelVAEREBROAA" 17752
"DK20132255838" 0
"NovanaModelBjoerupBaek" 1437.9
"NovanaModelFribroedreAA" 13249
"NovanaModelFribroedreAA" 13249
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Matt J
2021년 7월 27일
You have duplicate instances of names on the left with different values on the right. How would you wish to resolve that?
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Walter Roberson
2021년 7월 27일
findgroups(), and use the group numbers to splitapply() where the work function is @(x){x} . The results should be a cell array.
Now take the second output from the findgroups, the IDs output, which should be a cell array
struct('name', IDs, 'Qvolume', results_of_splitapply)
In the case where the values are cell array, then struct will create a struct array.
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Walter Roberson
2021년 7월 29일
C has entries of different lengths; it is not clear what it means to sort it? If you mean you want each one to be sorted within itself then change to @(x){sort(x)}
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