# simple combinations between cells

조회 수: 3(최근 30일)
Riccardo Tronconi 2021년 7월 20일
댓글: Riccardo Tronconi 2021년 7월 20일
Dear guys I'm looking for calculating the simple combinations between 3 cell:
T{1}=
Column 1 Column 2
3.29468361984674 3.24793763967276
3.25488582798159 3.33467494150750
3.30016433354633 3.30779418978228
3.36715866345752 3.17459467737618
3.42871475496273 3.18335187435669
3.30662100520200 3.16100391098778
T{2}=
Column 1 Column 2
2.69361371618303 3.57755708771298
2.56422065002361 3.57364773072377
2.66103273449339 3.54110582681669
2.60486706822838 3.55023611776072
2.60797207622599 3.58518248687590
2.65230479016750 3.50848441872052
T{3}=
Column 1 Column 2
3.12870601260590 4.33208439890896
3.14007960123577 4.37853754127380
3.03522738819268 4.35174951763305
3.16142049026022 4.28790024805517
2.98099119386563 4.05129787027474
2.97887698391243 4.28015976006215
Since the simple combinations are 3. I'm looking for
S{1}= [T{1} T{2}]
S{2}= [T{2} T{3}]
S{3}= [T{3} T{1}]
How to do that without a for loop?

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### 채택된 답변

Rik 2021년 7월 20일
편집: Rik 2021년 7월 20일
It can probably be done without a loop, but why do you want that? Loops are very efficient (as long as there isn't a builtin vectorized alternative).
T={1,2,3};
ind_list=nchoosek(1:numel(T),2)
ind_list = 3×2
1 2 1 3 2 3
This is not the order you want, so we will need to use something else:
ind_list=(1:numel(T)).'+(0:1);
ind_list=mod(ind_list,numel(T));
ind_list(ind_list==0)=numel(T);
ind_list
ind_list = 3×2
1 2 2 3 3 1
Now we can loop through the rows of ind_list to create S:
S=cell(size(ind_list,1),1);
for n=1:size(ind_list,1)
tmp=T(ind_list(n,:));
tmp=horzcat(tmp{:});
S{n}=tmp;
end
S
S = 3×1 cell array
{[1 2]} {[2 3]} {[3 1]}
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Riccardo Tronconi 2021년 7월 20일
thank you very much!!!

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