fetching data from array
조회 수: 1 (최근 30일)
이전 댓글 표시
I have a set of values as
G=[1 1 1 1 2 2 1 2 3 2 2 1 3 3]
in this there are 14 values,i want to fetch as following
there are 4 ones continously so i want to take first 1 ,then 2 2's continously ,i need first 2 ,then only 1 ,so i need to take that
So the output will be [1 2 1 2 3 2 1 3] with index positions [1 5 7 8 9 10 12 13]
kindly help
댓글 수: 0
채택된 답변
Andrei Bobrov
2013년 9월 19일
편집: Andrei Bobrov
2013년 9월 19일
G=[1 1 1 1 2 2 1 2 3 2 2 1 3 3];
G1 = G(:);
l = [true;diff(G1(:))~=0];
out = [G1(l),find(l)]
댓글 수: 0
추가 답변 (1개)
Jan
2013년 9월 19일
편집: Jan
2013년 9월 19일
[value, number, index] = RunLength(G)
Then value and index are the wanted results.
If you have problems to compile the fast MEX file, you can use RunLength_M from this submission instead. If you process millions of elements and runtime matters, be sure to use the compiled version.
참고 항목
카테고리
Help Center 및 File Exchange에서 Matrix Indexing에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!