Determine the length of a 3D cell array (?) within a struct

Hi together,

you find a MATLAB file in the dropbox-link, containing a 1x1 struct M:

https://www.dropbox.com/sh/a7ezk1v4pmd7ywz/3QiRY4XunO

This struct contains cell-arrays d00 to d15 (I'm not sure if these are cell arrays or something else). Each d** has three dimensions.

The first two dimensios are 3 and 4 (3x4). The third dimension is varying from d** to d**.

I want to extract the entries of the third dimension within a loop. Therefor I have to determine the lentgh of this third dimension for every d**.

Somebody can give me some advice?

Thanks a lot for help in advance! Ka Me

[Jan]

Please do not cross-post.

Answer 1

[Jan]

The solution would be trivial, if you avoid using "d00", "d01" etc as names of the variables. Hiding an index in the name is a very bad idea, which provokes such troubles. Better use a cell: d{1}, d{2}, ... Then:

dim3 = cellfun('size', d, 3)

Answer 2

[Ka]

Thanks a lot for the answer, Jan Simon.

You are right about the indexing within the name. However, I am using the program of someone else and I am not sure if I can manage to change the naming if it's a bit confusing.

What you suggest is making a cell array d with dimension 1x15, i.e. entries 0 to 14. Each entry contains a three dimensional matrix 3x4x?. Is this what you mean?

When I then use

 dim3 = cellfun('size', d, 3)

Will I get the third dimension of each of the 15 d-entries?

If I am not able to change the naming, is there a another way doing it?

Thanks again!

Answer 3

[Ka]

I just found out that you can get the dimensions of this d-cell-arrays by dynamic adressing:

size(M.d**)

   =   3   4   ...

Thanks for commenting again!