ํ•„ํ„ฐ ์ง€์šฐ๊ธฐ
ํ•„ํ„ฐ ์ง€์šฐ๊ธฐ

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์ด ์งˆ๋ฌธ์€ ๋งˆ๊ฐ๋˜์—ˆ์Šต๋‹ˆ๋‹ค. ํŽธ์ง‘ํ•˜๊ฑฐ๋‚˜ ๋‹ต๋ณ€์„ ์˜ฌ๋ฆฌ๋ ค๋ฉด ์งˆ๋ฌธ์„ ๋‹ค์‹œ ์—ฌ์‹ญ์‹œ์˜ค.

A rectangular box without a lid is to be made from 27๐‘š2 of cardboard. Find the maximum volume of such a box

์กฐํšŒ ์ˆ˜: 1 (์ตœ๊ทผ 30์ผ)
Rohan P
Rohan P 2021๋…„ 7์›” 1์ผ
๋งˆ๊ฐ: John D'Errico 2021๋…„ 7์›” 1์ผ
plz tell the answer if u know
  ๋Œ“๊ธ€ ์ˆ˜: 3
Rohan P
Rohan P 2021๋…„ 7์›” 1์ผ
tq for the reply bro i know the solution ibut i dont know the matlab code and the due is today
DGM
DGM 2021๋…„ 7์›” 1์ผ
This is a typical calculus 1 problem. You can do this as your course intends or approach it graphically to build your expectations/intuition. There are plenty of examples of solving this the intended way. The obvious thing to recognize is that for volume to be maximized for a fixed surface area, the bottom of the box must be square. This reduces the problem to a simple 1D maximization task. Express the volume as a function of area and width (or area and height). Treat the chosen dimension as the independent variable, and find the width (or height) at which the slope of V = 0. Back calculate to find the volume and remaining dimensions.

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์ด ์งˆ๋ฌธ์€ ๋งˆ๊ฐ๋˜์—ˆ์Šต๋‹ˆ๋‹ค.

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