필터 지우기
필터 지우기

Error in defining symbolic function

조회 수: 2 (최근 30일)
Akshay Kumar
Akshay Kumar 2021년 6월 28일
답변: Amit Bhowmick 2021년 6월 29일
Trying to define a symbolic function to calculate its derivative. My attempted code is attached.
I am getting following error " The following error occurred converting from sym to double:
Unable to convert expression containing symbolic variables into double array. Apply 'subs' function
first to substitute values for variables."
Any help will be highly appreciated.
close all; clear; clc;
syms g(a,b)
g = output(a,b);
function out = output(a,b)
for i = 1:10
p(i) = i^2+a*b;
if i==1
q(i) = 2;
else
q(i)= p(i-1);
end
end
out = sum(p.*q);
end

채택된 답변

Amit Bhowmick
Amit Bhowmick 2021년 6월 29일
Hope this will work
close all;
clear;
clc;
syms a b g(a,b) %Changes
g = output(a,b);
function out = output(a,b)
for i = 1:10
p(i) = i^2+a*b;
if i==1
q(i) = str2sym(num2str(2));%Changes
else
q(i)= p(i-1);
end
end
out = sum(p.*q);
end
%output
%g =
%2*a*b + (a*b + 1)*(a*b + 4) + (a*b + 4)*(a*b + 9) + (a*b + 9)*(a*b + 16) + (a*b + 16)*(a*b + 25) + (a*b + 25)*(a*b + 36) + (a*b + 36)*(a*b + 49) + (a*b + 49)*(a*b + 64) + (a*b + 64)*(a*b + 81) + (a*b + 81)*(a*b + 100) + 2;

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Assumptions에 대해 자세히 알아보기

제품


릴리스

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by