Writing a function that stops after three odd numbers have been found in a list.

I'm trying to write a script that will find the first three odd numbers in a list if there aren't three it should display "0". My current script determines if a single number is wrong but it doesn't go further than that.

function [ r ] = MyMod( x,y )

    while x >= 0
    x=x-y;
    end

    r=x+y;

    if r>0 disp('odd')
    end

end

Thanks for any help in advance.

Answer 1

[Youssef Khmou]

try to enhance this version :

 function Y=MyMod(X)
 %  List X
N=length(X);
Y=zeros(N,1); %  solution
ctr=1;   %  Counter
for t=1:N
    if mod(X(t),2)~=0
        Y(ctr)=X(t);
        ctr=ctr+1;
    end
end
Y=Y(1:3); %  First three

 if sum(mod(X,2))==0
    disp('0');
end

Answer 2

[Image Analyst]

I presume the implied question here is "How do I do it?" Here's one way:

% Create sample data
% Uncomment one of these
% m = [2 4 5 6 7 9 2 1 0] % Case with >3 odd #'s
m = [2 2 4 3 5 2] % Case where 0 should be displayed

% Now, find the first 3 odd values, displaying 0 if there are less than 3.
oddIndexes = find(mod(m, 2))
if length(oddIndexes) >= 3
  out = m(oddIndexes(1:3))
else
  out = 0
end

Answer 3

[Michael]

Thank you for the help reading through both of your functions helped me to understand how to attack this problem and create my own solution.