could anyone help me to solve the issue in the following command
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when i run the command
B = arrayfun(@(N) randi(2,N), repelem((1:3).',5), 'uniform', 0)
i am getting B = 15×1 cell array
{[ 1]}
{[ 1]}
{[ 1]}
{[ 2]}
{[ 2]}
{2×2 double}
{2×2 double}
{2×2 double}
{2×2 double}
{2×2 double}
{3×3 double}
{3×3 double}
{3×3 double}
{3×3 double}
{3×3 double} and the data inside are
3
2
2
2
2
[1,1;1,1]
[1,1;2,1]
[1,3;3,1]
[3,1;1,3]
[1,1;1,1]
[1,1,3;1,2,2;1,2,1]
[3,2,2;3,1,3;1,2,3]
[1,2,2;1,3,1;1,2,3]
[3,1,1;3,3,1;3,2,3]
[3,2,1;3,1,1;3,2,1]
but I actually need B =
15×1 cell array
{1×1double}
{1×1 double}
{1×1 double}
{1×1 double}
{1×1 double}
{1×2 double}
{1×2 double}
{1×2 double}
{1×2 double}
{1×2 double}
{1×3 double}
{1×3 double}
{1×3 double}
{1×3 double}
{1×3 double} containing the following values
3
2
2
2
2
[1,1]
[1,1]
[1,3]
[3,1]
[1,1]
[1,1,3]
[3,2,2]
[1,2,2]
[3,1,1]
[3,2,1]
could anyone please help me to get it.
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Walter Roberson
2021년 6월 23일
B = arrayfun(@(N) randi(2,1,N), repelem((1:3).',5), 'uniform', 0)
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Walter Roberson
2021년 6월 24일
You have a fixed outcome, and you have no explainable reason for that particular outcome. You should just write static assignment statements.
Remember the fundamental rule of practical programming: get it working first, and worry about making it shorter or faster later. You have been held up for days trying to write these things in a compact way, when you could have just written something that got the required outcome and moved on to the next step.
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