How to create a struct

조회 수: 3 (최근 30일)
Chao Zhang
Chao Zhang 2021년 6월 19일
댓글: Chao Zhang 2021년 6월 20일
There is a simple way to create a struct like the following picture, i.e ROCK = struct('ROCK0', value1, 'ROCK44', value2, 'ROCK50',value3, ....)
I was curious, is there any other ways to create a struct like the above, so i use for loop to do it, and the code is:
for m = 1 : size(rock_code,1)%Assign values to the initial cell
row_index = rock(:,col_ind_rk) == rock_code(m);%determine the row index according to the corresponding rock codes
sub_rock{m} = rock(row_index,:);
end
% Create string for each sub_rock
str_rock = cell(1,size(rock_code,1));%create cell to store strings
for kk = 1 : size(rock_code,1)
str_rock{kk} = sprintf('ROCK%d',rock_code(kk));
end
% Assign strings to each sub_rock
%create struct to store string and values
ROCK = struct;
for ii = 1 : size(rock_code,1)
ROCK = struct(str_rock{1,ii},sub_rock{1,ii});
end
But there is only the name and value of the last rock (i.e. ROCK53) in this structure, so, is there any way to achieve this struct like using for loop or other methods, thanks!
  댓글 수: 2
Stephen23
Stephen23 2021년 6월 19일
If you have any choice on the data design, then the best solution is to avoid forcing meta-data into fieldnames and simply use to basic arrays:
data = {1x13,2x13,2x13, .. etc}
rock = [ 0, 44, 50,51,52,53]
This makes processing the (meta-)data simpler and more efficient.
Chao Zhang
Chao Zhang 2021년 6월 20일
Thanks!

댓글을 달려면 로그인하십시오.

채택된 답변

Jonas
Jonas 2021년 6월 19일
편집: Jonas 2021년 6월 19일
use
for ii = 1 : size(rock_code,1)
ROCK.(str_rock{ii}) = sub_rock{1,ii};
end
at the end if sub_rock cell entries are the values for the fields

추가 답변 (1개)

Jan
Jan 2021년 6월 19일
str_rock = sprintfc('ROCK%d', rock_code); % Undocumented
ROCK = cell2struct(str_rock(:), sub_rock(:));

카테고리

Help CenterFile Exchange에서 Structures에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by