quadratic curve from matrices determinant

조회 수: 2 (최근 30일)
laura bagnale
laura bagnale 2021년 6월 14일
댓글: laura bagnale 2021년 6월 14일
Hello everyone,
could someone help me please?
I would like to obtain the quadratic curve coming from the calculation of a 2x2 matrix determinant.
This is what I wrote in my code:
h = @(x,y,z) 3.*(x+5).^2 + (x + 5).*(y - 2) + (y - 2).^2;
syms x y z
w = h(x,y,z)
g = @(x,y,z) (x - 5).^2 - (x - 5).*(y - 3) + (y - 3).^2;
syms x y z
w1 = g(x,y,z)
Dhx = diff(h,x)
Dhy = diff(h,y)
Dgx = diff(h,x)
Dgy = diff(h,y)
p1 = Dhx * Dgy
expand(p1)
p2 = Dhx * Dgy
expand(p2)
exp1 = expand(p1)
exp2 = expand(p2)
Now I should do the difference between exp1 and exp2, but I can't do it.
I am new with the symbolic toolbox, so I have difficulties to pass from symbolic expressions to numerical values.
I guess there is a faster way to calculate the determinant of my matrix and thus get the quadratic function but I don't really know how to find it.
Thank you very much for your support!
Laura
  댓글 수: 3
Catalytic
Catalytic 2021년 6월 14일
You have a number of previous posts that you have not accepted answers to, though the answers seem to be fine. It is a disincentive for people to help you.
laura bagnale
laura bagnale 2021년 6월 14일
Oh OK, thank you very much.
I'm very sorry but I'm new and I didn't understand that it was important!
Thank you again!
Laura

댓글을 달려면 로그인하십시오.

답변 (0개)

카테고리

Help CenterFile Exchange에서 Assumptions에 대해 자세히 알아보기

제품


릴리스

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by