I'm ensure if this would be an efficient way to use Bisection Method to approximate x ^2 + x ^4 + 6 = x ^3 + x ^5 + 7 to produce the first 11 values of iteration

Using Bisection method on matlab to approximate x ^2 + x ^4 + 6 = x ^3 + x ^5 + 7 to find first 11 values of iteration. How can I show the list of 11 values of iteration when I run it?

f = @(x)(x^5-x^4+x^3-x^2+1);
a = input('Please enter lower limit, a: ');
b = input('Please enter upper limit, b:  ');

n= input('Please enter no. of iterations, n: ');
tol = input('Please enter tolerance, tol: ');

fa = f(a); f(b);
i=1;

while i <= n 
    c = (b-a)/2.0;
    p = a+c;
    fp = f(p);
    if abs(fp)<1.0e-20 | c<tol
        
       fprintf('\nApproximate solutino p = %11.8f\n\n',p);
       break;
    else 
        i=i+1;
        if fa*fp >0
            a = p;
            fa = fp;
        else
            b=p;
            
        end
    end
    
end

Answer 1

[KSSV]

Two options.

1. MAke it a function: BisectionMethod(f,a,b,n,tol) and give inputs and call.
2. Remove the lines input and define the variables straight away.

[John Grand]

*thumbs up