필터 지우기
필터 지우기

Using ndgrid in arbitrary dimensions

조회 수: 8 (최근 30일)
melampyge
melampyge 2013년 8월 13일
Hi,
I have a 3x20 matrix called b. If I use ndgrid like this:
[xx, xy, xz] = ndgrid(b(1,:),b(2,:),b(3,:));
I get 20x20x20 matrices for each parameter xx,xy and xz which is what I want in the case that b has 3 rows. My problem is, I need to generalize this, for example, b might be 4x20 matrix or 5x20 matrix. In these cases I need to write the code like this:
[xx, xy, xz, xa] = ndgrid(b(1,:),b(2,:),b(3,:),b(4,:));
So my question is, how do I generalize this to an arbitrary M dimension, that is, if I have b as a Mx20 matrix, how can I use ndgrid?

답변 (1개)

Sean de Wolski
Sean de Wolski 2013년 8월 13일
편집: Sean de Wolski 2013년 8월 13일
There's a fun exercise in crashing my computer. Don't use a large b ;)
b = magic(3); %example
bc = num2cell(b,1); %cells columnwise
clear bbc; %in case it exists
[bbc{1:numel(bc)}] = ndgrid(bc{:}); %use comma-separated list expansion on both sides
Note, instead of creating four new variables, I create a cell array that contains them. This scales much better!
  댓글 수: 4
melampyge
melampyge 2013년 8월 13일
Actually I want to do it this way. I made my matrix b smaller (after several Matlab and computer crashes) and after that I got an array bcc with 1x15 cells, now I need to create xx, xy, xz 15x15x15 matrices from these cells I guess.
melampyge
melampyge 2013년 8월 13일
But it seems like I can't seperate them with cell2mat.

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Logical에 대해 자세히 알아보기

태그

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by