Using ndgrid in arbitrary dimensions
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Hi,
I have a 3x20 matrix called b. If I use ndgrid like this:
[xx, xy, xz] = ndgrid(b(1,:),b(2,:),b(3,:));
I get 20x20x20 matrices for each parameter xx,xy and xz which is what I want in the case that b has 3 rows. My problem is, I need to generalize this, for example, b might be 4x20 matrix or 5x20 matrix. In these cases I need to write the code like this:
[xx, xy, xz, xa] = ndgrid(b(1,:),b(2,:),b(3,:),b(4,:));
So my question is, how do I generalize this to an arbitrary M dimension, that is, if I have b as a Mx20 matrix, how can I use ndgrid?
답변 (1개)
Sean de Wolski
2013년 8월 13일
편집: Sean de Wolski
2013년 8월 13일
There's a fun exercise in crashing my computer. Don't use a large b ;)
b = magic(3); %example
bc = num2cell(b,1); %cells columnwise
clear bbc; %in case it exists
[bbc{1:numel(bc)}] = ndgrid(bc{:}); %use comma-separated list expansion on both sides
Note, instead of creating four new variables, I create a cell array that contains them. This scales much better!
댓글 수: 4
melampyge
2013년 8월 13일
Sean de Wolski
2013년 8월 13일
Yes. You will hit memory limitations quickly since these n-nd arrays take a lot of memory!
melampyge
2013년 8월 13일
melampyge
2013년 8월 13일
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