Split digits into 2 matrices

I am trying to solve a card problem.

I get two hands as an imput (Let's say 5H 5C 6S 7S 10D and 2C 3S 6S 7S 10D)

For this I want to split suit and number and put them in 2 different matrices. (I ofcourse number the suits first).

I have found ways to split the digits of a number, but not to put them in 2 different matrices.

Answer 1

[Walter Roberson]

Different approaches:

cards = {'5H' '5C' '6S' '7S' '10D' 'QC' '3S' 'KS' '7S' '10D'}

cards = 1×10 cell array
    {'5H'}    {'5C'}    {'6S'}    {'7S'}    {'10D'}    {'QC'}    {'3S'}    {'KS'}    {'7S'}    {'10D'}

ranks1 = cellfun(@(c) c(1:end-1), cards, 'uniform', 0)

ranks1 = 1×10 cell array
    {'5'}    {'5'}    {'6'}    {'7'}    {'10'}    {'Q'}    {'3'}    {'K'}    {'7'}    {'10'}

suits1 = cellfun(@(c) c(end), cards, 'uniform', 0)

suits1 = 1×10 cell array
    {'H'}    {'C'}    {'S'}    {'S'}    {'D'}    {'C'}    {'S'}    {'S'}    {'S'}    {'D'}

ranks2 = regexprep(cards, '.$', '', 'once')

ranks2 = 1×10 cell array
    {'5'}    {'5'}    {'6'}    {'7'}    {'10'}    {'Q'}    {'3'}    {'K'}    {'7'}    {'10'}

suits2 = regexp(cards, '.$', 'match', 'once')

suits2 = 1×10 cell array
    {'H'}    {'C'}    {'S'}    {'S'}    {'D'}    {'C'}    {'S'}    {'S'}    {'S'}    {'D'}

ranks3 = extractBefore(cards, lettersPattern(1) + lineBoundary)

ranks3 = 1×10 cell array
    {'5'}    {'5'}    {'6'}    {'7'}    {'10'}    {'Q'}    {'3'}    {'K'}    {'7'}    {'10'}

suits3 = extract(cards, lettersPattern(1) + lineBoundary)

suits3 = 1×10 cell array
    {'H'}    {'C'}    {'S'}    {'S'}    {'D'}    {'C'}    {'S'}    {'S'}    {'S'}    {'D'}

ranks4 = extract(cards, asManyOfPattern(characterListPattern("A1234567890JQK"),1))

ranks4 = 1×10 cell array
    {'5'}    {'5'}    {'6'}    {'7'}    {'10'}    {'Q'}    {'3'}    {'K'}    {'7'}    {'10'}

suits4 = extract(cards, characterListPattern("CDHS"))

suits4 = 1×10 cell array
    {'H'}    {'C'}    {'S'}    {'S'}    {'D'}    {'C'}    {'S'}    {'S'}    {'S'}    {'D'}

ranks5 = regexp(cards, '[0-9AJQK]+', 'match', 'once')

ranks5 = 1×10 cell array
    {'5'}    {'5'}    {'6'}    {'7'}    {'10'}    {'Q'}    {'3'}    {'K'}    {'7'}    {'10'}

suits5 = regexp(cards, '[CDHS]', 'match', 'once')

suits5 = 1×10 cell array
    {'H'}    {'C'}    {'S'}    {'S'}    {'D'}    {'C'}    {'S'}    {'S'}    {'S'}    {'D'}