how can I concatenate [aa,bb]?

clear all

close all

clc

x = linspace(1,50,25);

a = 100;

for n = 1:25

aa(1,1) = x(n).*9.81.*(a\x(n)).^2

if aa <= 50

disp('its valid')

elseif aa >= 51 && aa <= 75

disp('its valid but bigger')

else

disp('out of control')

end

end

y = linspace(1,100,25);

b = 200;

for m = 1:25

bb(1,1) = y(m).*9.81.*(a\y(m)).^2

if bb <= 50

disp('its valid')

elseif bb >= 51 && bb <= 75

disp('its valid but bigger')

else

disp('out of control')

end

end

for d = 1:25;

A(d) = [aa,bb]

end

Answer 1

[Mathieu NOE]

hello

I believe there are a frew mistakes as aa and bb are not indexed in the for loops , so you have a scalar that will be overwritten at each for loop iteration

therefore I modified your code this way :

clear all
close all
clc
x = linspace(1,50,25);
a  = 100;
for n = 1:25
%     aa(1,1) = x(n).*9.81.*(a\x(n)).^2
    aa(n) = x(n).*9.81.*(a\x(n)).^2;
    if aa(n) <= 50
        disp('its valid')
    elseif aa(n) >= 51 && aa(n) <= 75
        disp('its valid but bigger')
    else
        disp('out of control')
    end
end
y = linspace(1,100,25);
b = 200;
for m = 1:25
        
%     bb(1,1) = y(m).*9.81.*(a\y(m)).^2
    bb(m) = y(m).*9.81.*(a\y(m)).^2;
    
    if bb(m) <= 50
        disp('its valid')
    elseif bb(m) >= 51 && bb(m) <= 75
        disp('its valid but bigger')
    else
        disp('out of control')
    end
end

A = [aa' bb'];

[Abhinandan Angadi]

thanks for rectifying.

[Mathieu NOE]

you're welcome