Combine logical cell array based on 'or' condition

I am trying to combine all elements of a cell array containing multiple logical arrays into a single array, where the single array has a true value if any of the logical arrays contain true at that index.

C{1,1} = logical([1;0;0;0;0]);
C{1,2} = logical([0;1;0;0;0]);
C{1,3} = logical([0;0;1;0;0]);

I know that if I wanted to combine 2 of the elements, I could do this:

or(C{1,1}, C{1,2})

This would give me the output:

ans =

  5×1 logical array

   1
   1
   0
   0
   0

Is there a way to combine all 3 logical arrays and get this as output? (preferably in a single operation)

ans =

  5×1 logical array

   1
   1
   1
   0
   0

Answer 1

[DGM]

Maybe something like this:

% test array
C{1,1} = logical([1;0;0;0;0]);
C{1,2} = logical([0;1;0;0;0]);
C{1,3} = logical([0;0;1;0;0]);

Cl = any(cell2mat(C),2)

Cl = 5×1 logical array
   1
   1
   1
   0
   0

[Alex Wooten]

Exactly what I was looking for, thanks!

Answer 2

[Daniel Bengtson]

You could do something like this.

C{1,1} = logical([1;0;0;0;0]);
C{1,2} = logical([0;1;0;0;0]);
C{1,3} = logical([0;0;1;0;0]);

[~,wid] = size(C);

%false vector to use as a starting point
init = false(size(C{1,1}));

%ORs together every vector in C
for i = 1:wid
    init = init | C{1,i};
end

Answer 3

[David Fletcher]

C{1,1}|C{1,2}|C{1,3}