Interp2 a set of randomly sampled points?

조회 수: 2 (최근 30일)
MikeStein
MikeStein 2013년 7월 25일
Hello All,
I am given the following information with no guarantee on any particular order or sample spacing (there could be holes. Roughly on a hexagonal grid, but not precicely...)
- Vectors of X and Y locations corresponding to a same-sized vector of complex values which I want to interpolate.
I've written the following test case which works great:
% Simple test case first to test handling of phasors:
test = [0 2*pi 0.1;
-0.1 0 -2*pi;
0 0 0;]
test = exp(1i*test);
[testX, testY] = meshgrid(1:3)
interpX = [1.5; 2.5; 2.1];
interpY = [1.5; 1.5; 2];
testInterp = interp2(testX,testY,test, interpX, interpY);
angle(testInterp)
% It works!
Unfortunately, I don't get my data in these nicely formatted and arranged square matricies. I get them in vectors, which don't have any particular order. I modified the above code to mimic this, and get errors complaining that the vectors are no longer monotonically increasing... I've tried sorting the data by x or y, but I keep getting the errors. Since the x coords are coupled with the y coords, I can't sort both x and y at the same time (does that make sense?). Any way, maybe the code below helps:
test = [0 2*pi 0.1;
-0.1 0 -2*pi;
0 0 0;]
test = exp(1i*test);
[testX, testY] = meshgrid(1:3)
interpX = [1.5; 2.5; 2.1];
interpY = [1.5; 1.5; 2];
combinedVector = [testX(:), testY(:), test(:)];
combinedVector = sortrows(combinedVector, [2 1]);
testInterp = interp2(combinedVector(:,1),combinedVector(:,2),combinedVector(:,3), interpX, interpY);
angle(testInterp)
Thoughts?? -Mike

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MikeStein
MikeStein 2013년 7월 25일
Interesting function! I modified my script (below) to accept this, but it doesn't give the results I expect. They are close, but don't match the first test script I wrote (and is correct). Thoughts?
% Simple test case first to test handling of phasors:
test = [0 2*pi 0.1;
-0.1 0 -2*pi;
0 0 0;]
test = exp(1i*test);
testR = real(test);
testI = imag(test);
[testX, testY] = meshgrid(1:3)
interpX = [1.5; 2.5; 2.1];
interpY = [1.5; 1.5; 2];
Fr = scatteredInterpolant(testX(:), testY(:), testR(:))
Fi = scatteredInterpolant(testX(:), testY(:), testI(:))
angle(Fr(interpX, interpY) + 1i*Fi(interpX, interpY))
Thanks!
  댓글 수: 3
dpb
dpb 2013년 7월 25일
Jim has it basically between interp2 and triscattered
I don't know about the FEX submission but you can also look at
*griddata"
There's a decent background section in the doc's on interpolating scattered data that outlines at least the basics of the methods implemented
MikeStein
MikeStein 2013년 7월 29일
Thanks All!! That was the guidance I needed!! -Mike

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