Several tangent vectors on curve

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Viktor Karlsson
Viktor Karlsson 2021년 5월 14일
댓글: Viktor Karlsson 2021년 5월 17일
Hello,
I have the following curve plotted:
Now, I want 10 tangent vectors along this curve and I can't seem to figure out how to write the code for this to work. I wrote the following:
t = linspace(-2.5,2.5,100);
x = t.^3 - 4*t;
y = t.^2;
plot(x,y,'LineWidth',2)
axis equal
hold on
i=1:10:100;
ts=t(i);
xs=x(i);
ys=y(i);
tx = ts.^3 -4*ts;
ty = ts.^2;
quiver(tx,ty,xs,ys,'LineWidth',2,'Color','r')
hold off
and the result is.. not quite it:
Any help or advice is appreciated.

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the cyclist
the cyclist 2021년 5월 14일
편집: the cyclist 2021년 5월 14일
Well, you never actually calculated the tangent, so it is not that surprising you didn't get the correct result.
t = linspace(-2.5,2.5,100);
x = t.^3 - 4*t;
y = t.^2;
dydt = 2*t;
dxdt = 3*t.^2 - 4;
dydx = dydt./dxdt;
i=1:10:100;
ts=t(i);
xs=ones(size(i));
ys=dydx(i);
tx = ts.^3 -4*ts;
ty = ts.^2;
figure
hold on
plot(x,y,'LineWidth',2)
quiver(tx,ty,xs,ys,'LineWidth',2,'Color','r')
axis equal
Apologies for rearranging your code to my liking. See this page for the math of calculating the tangent of a parametric equation. (You'll need to be careful if dx/dt is ever zero, because you divide by that.)
Also, I was lazy and just set the length of the x-component of the tangent vector to (positive) 1, then calculated the y-component. You probably want something less lazy.
  댓글 수: 3
the cyclist
the cyclist 2021년 5월 14일
As I mentioned, I always defined the x-component of the tangent vector as +1; therefore, it will always be toward the right.
The parametric equation has no inherent "direction", and the tangent line extends in both directions from any given point.
Viktor Karlsson
Viktor Karlsson 2021년 5월 17일
I understand, thank you helping!

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