after applying a filter -i design- to a real signal, it returns complex signal after ifft

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[x,fs]=audioread('some.wav');
n=length(x);
t = ((0:n-1)*(fs/n));
y=fft(x);
f = ((0:n-1)*(fs/n));
y0 = fftshift(y);
f0 = ((-n/2:n/2-1)*(fs/n));
noise = find(abs(y0) == max(abs(y0)));
noiseW= [2*pi*f0(noise(1)) 2*pi*f0(noise(2))];
z1=exp(1i*noiseW(1));
z2=exp(1i*noiseW(2));
z=exp(1i*2*pi*f0);
H=(1-z1*(z.^-1)).*(1-z2*(z.^-1));
out0=y0.*(H.');
out=ifftshift(out0);
signal=ifft(out);
audiowrite('output.wav',final,fs);
  댓글 수: 2
Daniel Pollard
Daniel Pollard 2021년 5월 14일
I'm not sure I understand the problem. The FFT (and the IFFT) produce complex outputs by their definition. Could you give some more details? What were you expecting to happen?
Hamza AKYILDIZ
Hamza AKYILDIZ 2021년 5월 14일
some.wav file is a real signal. after i apply the filter H to it, i expect it to be still real after ifft.

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Paul Hoffrichter
Paul Hoffrichter 2021년 5월 14일
Your imaginary part only is non-zero due to the usual floating point roundoffs and truncations. Fix this using round:
signal=ifft(out);
signalRound = round(signal, 10);

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