a problem with a function
조회 수: 3 (최근 30일)
이전 댓글 표시
hi all ! i wrote this simple function
%
function [ output_args ] = fract_int16( input_args )
if input_args<0
output_args=round(2^16+input_args*2^15);
else
output_args=round(input_args*2^15);
end
end
when i use it for negative number for exemple
%
fract_int16(-0.9133)=35609
fract_int16(0.3481)=11409,
both values ARE TRUE
but when use this function in an array i get a false value
%
A=[-0.9133 0.3481]
fract_int16(A)=[-29927 11407]
this is wrong!!
did i make i mistake in writing this function?
thank you all
댓글 수: 0
채택된 답변
David Sanchez
2013년 7월 23일
Try this out:
input_args = [-0.9133 0.3481];
output_args = zeros(size(input_args));
for k=1:length(input_args)
if input_args(k)<0
output_args(k)=round(2^16+input_args(k)*2^15);
else
output_args(k)=round(input_args(k)*2^15);
end
end
댓글 수: 0
추가 답변 (2개)
Narges M
2013년 7월 23일
편집: Narges M
2013년 7월 23일
Yes, your function is designed to work with one value, and see if that's less than zero or not. So if you want to use it for arrays you need to use a loop either in the function or when calling it. Right now, if any of the array values are less than zero, if would fire TRUE, and then the output would be calculated for the whole array.
댓글 수: 0
Jan
2013년 7월 23일
And a faster vectorized version:
function output_args = fract_int16(input_args)
output_args= 2^16 * (input_args < 0) + round(input_args * 2^15);
end
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Data Type Conversion에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!