Multiplying anonymous function by a vector

조회 수: 9 (최근 30일)
Stanley Ka
Stanley Ka 2021년 4월 22일
편집: Walter Roberson 2021년 4월 22일
I'm trying to plot 4 different graphs in respect to 4 different function handles for 10 revolutions using for loop. I've created a function file and a m-file but the error Operator '.*' is not supported for operands of type 'cell' just keeps popping out.
%% Function file
function [x,y] = my_polar(fhandle, N)
th = 0:0.01:2*pi;
for i =0:N-1
x = fhandle.*cos(th);
y = fhandle.*sin(th);
th = th+2*pi;
end
end
%% m-file
f1 = @(th) exp(0.01*th).*sin(5*th);
f2 = @(th) sin(10*th) + 0.15;
f3 = @(th) sin(0.5*th).*(0.85 + sin(th));
f4 = @(th) 10 + sin(2*pi.*th);
fset = {f1;f2;f3;f4};
for i=1:4
subplot(2,2,i);
[x,y] = my_polar(fset(i), 10);
plot(x,y);
title(char(fset(i)));
end

채택된 답변

Cris LaPierre
Cris LaPierre 2021년 4월 22일
You have defined your function to have an input - th. Therefore, when you use your function handle, you have to supply it an input. Perhaps you meant to do the following?
x = fhandle(th).*cos(th);
The error message about 'cell' is because you add your function handles to a cell array, fset. When you use parentheses to index a cell array, it returns a cell array. Use braces to pass the function handle into the function.
[x,y] = my_polar(fset{i}, 10);
Your final error will be about trying to create a title from the function handle. You might find this answer insightful. You probably want to use func2str. Just be aware that it also does not work with cells.
  댓글 수: 1
Stanley Ka
Stanley Ka 2021년 4월 22일
It worked! Thank you so much. I'm new to programming so I'm still learning a lot of things, but now I know that even different brackets can have so much impact on the entire code. Thanks again for replying so fast!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Performance and Memory에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by