How do you get a specific decimal accuracy with the fprintf function?

I want to display my r variable with 6 decimals, but I am not sure how to format the line. I could not really find how to with the documentation page and would appreciate some guidance, Thank you so much!!
fprintf("The estimated principle stress val is %6f .\n " + r )

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I know you can do format long, but I want it to be specifically 6 decimals.

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the cyclist
the cyclist 2021년 4월 20일
편집: the cyclist 2021년 4월 20일
Your r variable needs to be a second argument (not using a plus sign as you did).
r = pi;
fprintf("The estimated principle stress val is %9.6f.\n ",r)
The estimated principle stress val is 3.141593.
The %9.6f indicates that the output should use 6 decimal places, and field width of 9.

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도움말 센터File Exchange에서 Scope Variables and Generate Names에 대해 자세히 알아보기

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R2020b

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2021년 4월 20일

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2021년 4월 20일

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