Evaluating polynomial functions to get integer as answer

조회 수: 1 (최근 30일)
Rodrigo Toledo
Rodrigo Toledo 2021년 4월 4일
편집: Walter Roberson 2021년 4월 4일
I am trying to evaluate:
syms x y
eq = (x^2 + y^3 == 31)
solve(eq)
eqs = [x^2 + y^3 == 31, x^2 == 31 - y^3]
S = solve(eq,[x y])
S.x and S.y still not 2 and 3
i am expecting to get as answer two integer: x=2 and y=3. How can i do it?
Thanks

채택된 답변

Walter Roberson
Walter Roberson 2021년 4월 4일
편집: Walter Roberson 2021년 4월 4일
syms x y integer
eq = (x^2 + y^3 == 31)
eq = 
solx = solve(eq,x,'returnconditions',true)
solx = struct with fields:
x: [2×1 sym] parameters: [1×0 sym] conditions: [2×1 sym]
soly = solve(solx.conditions)
soly = 
3
X = subs(solx.x,y,soly)
X = 
Y = soly
Y = 
3
Caution: this kind of process will not generally attempt to find more than one solution for solx.conditions. But you could
soly = solve(eq,y,'returnconditions',true)
soly = struct with fields:
y: [3×1 sym] parameters: [1×0 sym] conditions: [3×1 sym]
solx = arrayfun(@solve, soly.conditions, 'uniform', 0)
Warning: Unable to find explicit solution. For options, see help.
solx = 3×1 cell array
{0×1 sym} {2×1 sym} {0×1 sym}
X = solx{2}
X = 
Y = subs(soly.y(2), x, X)
Y = 

추가 답변 (1개)

darova
darova 2021년 4월 4일
solve can be used for simple problems. Use fsolve or vpasolve to get numerical results
  댓글 수: 1
Walter Roberson
Walter Roberson 2021년 4월 4일
Not the point. The point is that solve() is having difficulty processing integer constraints in this case. fsolve and vpasolve have no chance of processing integer constraints.

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