any suggestion to store answer after for loop into a matrix to use later?

this is what i have so far, it only store the answer of the last entry of x (N) into matrix b, which was supposed to have all the binary entries for each entry of x (from 0 upto N). Any improvement I can make to achieve that?

function [x] = mybinplot(N)

x = 0:N;
for d = 0:N
    if d == 0
        b = 0;
    else
        p = 0;
        while 2^p <= d
            p = p + 1;
        end
        b = zeros(p,length(x));
        power = p-1;
        for ii = 1:length(b)
            if d >= 2^power
                b(ii) = 1;
                d = d - 2^power;
            end
            power = power - 1;
        end
    end
end
z = fliplr(b);
disp(z)

Answer 1

[Jan]

x = 0:N;
b = zeros(ceil(log2(N)), length(x));  % Move this BEFORE the loop to avoid overwriting
for d = 1:N
    p = 0;
    while 2^p <= d
       p = p + 1;
    end
    power = p-1;
    for ii = 1:p
        if d >= 2^power
            b(ii, d + 1) = 1;
            d = d - 2^power;
        end
        power = power - 1;
    end
end

But the result looks strange:

b =
     0     1     1     1     1     1
     0     1     0     0     0     0
     0     1     0     0     0     0

You forgot to mention, what your code should achieve.

By the way, v=ceil(log2(N)) is a vector. Then zeros(v, length(x)) is working, but a confusing exception. Better use the scalar ceil(log2(max(N))) .

[EDITED] Of course this works as good or bad as the original code also. I could not post a working version directly, because you did not explain, what you want to get. The actual question "store answer after for loop into a matrix to use later?" did not clarify this.

After reading your comment:

x   = 0:5;
Len = ceil(log2(max(x)));
z   = rem(floor(pow2(1-Len:0).' * x), 2);

Or with a loop:

x   = 0:5;
Len = ceil(log2(max(x)));
b   = zeros(Len, numel(x));
for k = Len:-1:1  % From bottom to top:
  b(k, :) = rem(x, 2);
  x       = floor(x / 2);
end

[Quoc Khang Doan]

What i want to achieve is convert every element in x, for example:

>> x = 0:5;
x = 0 1 2 3 4 5

into binary and store it into a matrix z like so:

>> mybinplot(5)
z = 
    0 0 0 0 1 1
    0 0 1 1 0 0
    0 1 0 1 0 1

thank you in advance