Creating matrix with diag command
조회 수: 2 (최근 30일)
이전 댓글 표시
I am trying to do this
a = input('enter a number: ')
for i=1:1:a
for j=1:1:a
z(i,j)= diag(a)
end
end
z
I enter 10 to create 10x10 matrix. I am trying to do corner to corner 1-10 like diag command and do other numbers 0. What is my mistake? I must do this with nested for-end.
댓글 수: 0
채택된 답변
Stephan
2021년 3월 21일
편집: Stephan
2021년 3월 21일
This is how a normal Matlab user would so this
z = diag(1:10)
z =
1 0 0 0 0 0 0 0 0 0
0 2 0 0 0 0 0 0 0 0
0 0 3 0 0 0 0 0 0 0
0 0 0 4 0 0 0 0 0 0
0 0 0 0 5 0 0 0 0 0
0 0 0 0 0 6 0 0 0 0
0 0 0 0 0 0 7 0 0 0
0 0 0 0 0 0 0 8 0 0
0 0 0 0 0 0 0 0 9 0
0 0 0 0 0 0 0 0 0 10
However:
a = input('enter a number: ')
z = zeros(a);
for ii=1:1:a
for jj=1:1:a
if ii == jj
z(ii,jj)= ii;
end
end
end
disp(z)
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Shifting and Sorting Matrices에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!