matrix for loop question

조회 수: 2 (최근 30일)
jana
jana 2013년 5월 30일
Suppose I have a matrix [1 2 3 5;1 3 4 5]. Each row represents a path and each column represents the nodes of that path. For example: for row 1 : 1-2-3-5 is a path with nodes 1, 2 ,3, 5(where one is the start node and 5 is the end node). I want to consider an arc and arcs following that arc. For example: I want to consider (1,2) and (2-3) and assign a cost to it. I wrote a code but its showing an error. please help!
for kkp = 1:size(R{ip},1) % R{ip} is my path matrix
for jjp = 1:size(R{ip},2)-1
for iip = 1:size (R{ip,2} -2)
up = R{ip}(kkp,jjp);
vp = R{ip}(kkp,jjp+1);
wp = R{ip}(kkp,jjp+2);
cost1 = wt(up,vp); %wt(i,j) is a cost matrix that i already inputed.
cost 2 = wt(vp,wp);
end
end
end

채택된 답변

Eugene
Eugene 2013년 5월 30일
You're indexing 'R' as a 1-D cell array at the start however in the third line you start indexing the 2nd dimension.
for iip = 1:size (R{ip,2} -2)
I think you meant
for iip = 1:size(R{ip},2) - 2
And a typo at (no space between 'cost' and '2'):
cost 2 = wt(vp,wp);
  댓글 수: 2
jana
jana 2013년 5월 30일
I've made the correction but it is still showing an error. My cost2 outpput is coming as zero but that is not right.
my wt matrix is :
wt =[0 2 4 0;1 0 5 3;4 5 0 5;0 3 5 0];
so if for path 1-2-3-4 cost1 should be 2 and cost2 should be 5 (for 2-3) and 5 (for 3-4) .
jana
jana 2013년 5월 30일
nevermind..I fixed it. Thanks.

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