sig_tr_sib=normpdf(norminv(cdf(gamma_sib,SIB)))/(pdf(gamma_sib,SIB)); %transformation
mu_tr_sib=SIB-norminv(cdf(gamma_sib,SIB)).*sig_tr_sib;
Undefined function 'expm1' for input arguments of type 'sym'.
Error in wblcdf>localwblcdf (line 94)
p = -expm1(-z);
Error in wblcdf (line 51)
[varargout{1:max(1,nargout)}] = localwblcdf(uflag,x,varargin{:});
Error in prob.WeibullDistribution.cdffunc (line 223)
[varargout{1:nargout}] = wblcdf(varargin{:});
Error in prob.ToolboxParametricDistribution/cdffun (line 16)
[varargout{1:nargout}] = this.cdffunc(x,pcell{1:min(end,this.NumParameters)},covarg{:},varargin{:});
Error in prob.TruncatableDistribution/cdf (line 153)
y = cdffun(this,x,varargin{:});
Error in NewTopplingRIA (line 348)
sig_tr_sib=normpdf(norminv(cdf(gamma_sib,SIB)))/(pdf(gamma_sib,SIB)); %transformation

답변 (1개)

Star Strider
Star Strider 2021년 3월 13일

0 개 추천

The expm function can accept symbolic arguments, however expm1 cannot.

댓글 수: 4

Walter Roberson
Walter Roberson 2021년 3월 13일
Expanding further: many functions in the statistics toolbox cannot accept symbolic values.
A lot of the stats functions have simple bounds tests such as the inverse cdf checking that the inputs are in the range 0 to 1. Symbolic expressions cannot use those tests: if x<0 cannot be resolved when x involves a symbolic variable.
Star Strider
Star Strider 2021년 3월 13일
Walter — Thank you for expanding on that.
The solution would likely be to use erf and its friends, that do take symbolic arguments. They would need to be modified slightly to work as the normal distribution, however that information is in the documentation.
MANOJ KUMAR
MANOJ KUMAR 2021년 3월 14일
Thank you.
Star Strider
Star Strider 2021년 3월 14일
My pleasure.

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카테고리

도움말 센터File Exchange에서 Symbolic Math Toolbox에 대해 자세히 알아보기

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2021년 3월 13일

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2021년 3월 14일

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