Adding a function with a specific value

Hello. I am trying to add a simple value to a function, but it rejects me every time. I think i've tried every noob idea, and was all out of luck. What am i missing?

f=@(x) x^4-7*x^3+9*x^2+7*x-5; 
f+10

[the cyclist]

Which of the following is what you want?

• Define a new function such that f2(x) is always 10 greater than f(x), for all values of x
• Find the value of f(x) at a particular value of x, and add 10 to that
• Something else [please describe]

[Jan]

Because the code is not working, we cannot guess, what you want to achieve.

Remember to post a copy of the error message, if you get one.

Answer 1

[Jan]

You define f as a function handle. Then you have to call it with an argument also:

f = @(x) x^4 - 7 * x^3 + 9 * x^2 + 7 * x - 5; 
f(5) + 10   % 15

Or do you want to create another function?

g = @(x) f(x) + 10
g(5)  % Of course also 15

[Max Olsen]

I feel like i tried that already without abything happening, but somehow this helped at doing exactly what i wanted (I wanted to use fzero to find the values at where the function was at -10, but that needed a function that had both the old function and the +10)