How to generate a list of random ID which can later be used instead of participant name?
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Hello every one,
I want to programm a code in which I can generate a list of random ID to use as test person ID later during my experiments.
- Each ID has to be consisted of 2 letters as well as 2 digits (e.g., 2g9e)
I would be so thankful if somebody could advise me how to do so.
Best regards,
Parishad
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the cyclist
2021년 3월 4일
May I ask why this particular format? It would certainly be easier to do pure numerical digits.
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Paul Hoffrichter
2021년 3월 4일
Due to the cyclist remark about homework, I am just starting the script. It leaves out certain patterns like 'a9a9' since it is just using combinations. How you rearrange the unique patterns is up to you.
a_26_2 = nchoosek('a':'z',2);
n_10_2 = nchoosek('0':'9',2);
a_26_2f = [a_26_2; fliplr(a_26_2)]; % gives 650 2 letter unique alpha strings
n_10_2f = [n_10_2; fliplr(n_10_2)]; % gives 90 2 letter unique numeric strings
By merging all possibilities, you can get 650*90 (almost 60,000) unique 4 char id's.
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Walter Roberson
2021년 3월 4일
We are not told that letters are restricted to lowercase.
We are also not told to avoid easily confused possibilities such as l0lO
Paul Hoffrichter
2021년 3월 5일
True. But if homework as @the cyclist was trying to determine, getting a start is better than nothing.
추가 답변 (1개)
David Hill
2021년 3월 4일
Yes, a strictly numerical format would be much easier.
a=[randperm(10,2)+47;randperm(26,2)+96];
a=char(a(:)');
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Walter Roberson
2021년 3월 4일
We are not promised that the order of digits and letters is fixed, just that there are two of each.
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