count the number of columns 0 and 1 in a barcode image column 0 is black bars and 1 is a white bars

I have a barcode image. Please help me how to count the number of columns 0 and 1 in a barcode image only consist column 0 is black bars and 1 is a white bars Please help me.

Answer 1

[Ivan van der Kroon]

Hey, convert it to logical class and then sum over a column (or columns). If your image is variable Im, go to logical with

BW = im2bw(Im);

Possibly with threshold if your image is not so very black-white in the beginning, see the im2bw help-file. To sum over the columns:

barcode = sum(BW,2);

Where the 2 is for the correct dimension. You can limit BW to a single or multiple row(s) if you want to.

Note that you are counting the number of white pixels in this case. To count the blacks use (1-BW) in the above and if your barcodewidth consists of multiple pixels divide the answer by this number.

[yen]

if I have a imageM

M=

[1 1 0 0 0 0 1 1 1 1 1 0 0 0 1

1 1 0 0 0 0 1 1 1 1 1 0 0 0 1

1 1 0 0 0 0 1 1 1 1 1 0 0 0 1

1 1 0 0 0 0 1 1 1 1 1 0 0 0 1]

how can I count number column 1 and 0?

with M, colmn1=i;

i=8

column0=j;

j=7

Answer 2

[Ivan van der Kroon]

>> sum(M,2)

ans =

     8
     8
     8
     8

Answer 3

[Matt Fig]

M=[1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
   1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
   1 1 0 0 0 0 1 1 1 1 1 0 0 0 1
   1 1 0 0 0 0 1 1 1 1 1 0 0 0 1] 

cnts = histc(double(all(M)),[0 1])

Or, if there will never be a column with some 1s and some 0s, then:

histc(double(M(1,:)),[0 1]) % I don't know if M is logical or what.