Find first index that exceeds condition

To elaborate and ensuring my questions are specific, I have a dataset and their index:

[1,2,3,4,5,6,7,8,9]

[1,4,8,0,0,1,9,0,3]

Say I would like to find the index and value of the 1st value > 2 after value (8)

Which means my desired output would look like this:

[7]

[9]

Normally, I would have a table of starting indices, but this is just a random sample to keep it short.

How do I code this?

Thanks.

Answer 1

[KALYAN ACHARJYA]

"I would like to find the index and value of the 1st value > 2 after value (8)"

Is this?

data=[1,4,8,0,0,1,9,0,3]
idx8=find(data==8)
idx=find(diff(data)<0)
result_idx=idx(idx>idx8(1))

Answer would be 7 only, can you verify again?

[Jonathan Cheong]

Hey Kalyan, thanks for the answer.

Although it technically produces the correct output, it's more like hard coded.

Is there a method to code so that it applies across an entire array consistently?

For example I have attached files: starting index (fdd2), data (rain2).

Same situation just in the format of an array.

[Jonathan Cheong]

The data won't be exactly 0 but it will be less than 2.

Hence the code should stop when the 1st value greater than 2 after the starting index is reached