Adding a new column to a table
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I have the following database (Male_Data), its a 3101x16 table.
I want to add a new column in which I get values between 1 and 3 depending on the value I have on the QTCorrected column.
1 if the value is between 330 - 360
2 if the value is between 361 - 390
3 if the value is between 391 - 470.

% This is all I can think of
% The name of the column I want to add is QTSyndrome
Male_Data.QTSyndrome = Male_Data.QTCorrected () %I'm thinking about adding some kind of if statement inside the
% parenthesis but my attempts haven't been succesful so far
Any help is appreciated
Thanks
답변 (1개)
Star Strider
2021년 2월 25일
One approach:
T1 = table(randi([330 470],10,1), 'VariableNames',{'QTcorrected'}); % Create Data
QTc = @(x) 1*((x>=330)&(x<=360)) + 2*((x>=361)&(x<=390)) + 3*((x>=391)&(x<470)); % Classify
T1.NewColumn = QTc(T1.QTcorrected); % Add Variable
.
댓글 수: 5
Daniela Valdez
2021년 2월 25일
Daniela Valdez
2021년 2월 25일
Star Strider
2021년 2월 25일
As always, my pleasure!
I’m not certain about the ‘Fliename’ column, or that you’d need to add it separately, since if you use readtable to import the file in the image, it should already exist. There shouldn’t be any reason to add it again.
I’d have to have your data to experiment with to be certain, however simple horizontal concatenation would likely be easiest, if ‘Filename’ was already a table object.
See Build Table by Assigning Variables Individually for details on how best to add variables to existing table objects.
Daniela Valdez
2021년 2월 25일
Star Strider
2021년 2월 25일
As always, my pleasure!
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