unique values in array

Hi all,

I'm sure this is probably very easy but I can't seem to crack it. I've got an array like so:

timing =

         10
          5
          5
          5
          5
          5
          5
          5
          5
          5
          5
         10
         10
         10
         10
         10
         10
         20
         20
         20
         60
         60
         60
         60
         60
         30
         30
         10];

I'd like to produce a table of the data which shows the number of entries, i.e.

1 x 10
10 x 5
6 x 10
3 x 20 
5 x 60
3 x 30
1 x 10

This array changes length (and values) each time I run my code.

Using the "unique" command would have this done in a line of code, but the fact that same value repeats itself later in the array is making it a lot more hassle!

Any help greatly appreciated

Thanks Jim

Answer 1

[Grzegorz Knor]

Simply idea is to use loop:

f = [1 , timing(1)];     
for k=2:numel(timing)
    if timing(k)~=timing(k-1)
        f(end+1,2)=timing(k);      
    end
    f(end,1) = f(end,1)+1;
end

[Jim O'Doherty]

Thanks Grzegorz, that works absolutely perfectly for anything I threw at it

Jim

[Grzegorz Knor]

And another a little tricky solution:

[diff([0;find(diff([timing;rand()]))]) timing(find(diff([timing;rand()])))]