The following errors occurred in solving the tripartite evolutionary game,does anyone know the reason?
Here is the error.
索引超出矩阵维度。
出错 differential (line 2)
dxdt=[x(1)*(1-x(1))*(10-3*x(3)-5*x(2));x(2)*(1-x(2))*(4*x(1)+12.6*x(3)-9);
出错 odearguments (line 87)
f0 = feval(ode,t0,y0,args{:}); % ODE15I sets args{1} to yp0.
出错 ode45 (line 115)
odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);
出错 run (line 5)
[T,Y]=ode45(@differential,[0,20],[i j m]);
The code is as follows.
function dxdt=differential(x,t)
dxdt=[x(1)*(1-x(1))*(10-3*x(3)-5*x(2));x(2)*(1-x(2))*(4*x(1)+12.6*x(3)-9);
x(3)*(1-x(3))*(3*x(1)*x(2)+20.4*x(2))]
%t是演化的步长和时间
end
--------------------------------------
clear all
for i=0.1:0.2:0.9
for j=0.1:0.2:0.9
for m=0.1:0.2:0.9
[T,Y]=ode45(@differential,[0,20],[i j m]);
figure(1)
grid on
plot(T,Y(:,1),'r-','lineWidth',1);
hold on
plot(T,Y(:,2),'b--','lineWidth',1);
hold on
plot(T,Y(:,3),'g*','lineWidth',1);
hold on
end
end
end

댓글 수: 2

James Tursa
James Tursa 2021년 2월 20일
Please delete these images and instead post your code and error messages as text highlighted with the CODE button. We can't copy & run pictures.
Erin Sausage
Erin Sausage 2021년 2월 21일
Oh thanks for reminding me. I re-edit the post as you say, if possible, could you plz help me to see why such the error occurs?

댓글을 달려면 로그인하십시오.

 채택된 답변

Walter Roberson
Walter Roberson 2021년 2월 21일

1 개 추천

function dxdt=differential(x,t)
needs to be
function dxdt=differential(t,x)

댓글 수: 3

Erin Sausage
Erin Sausage 2021년 2월 21일
oh I got it! Thanks you! But why my teacher can run with such code, mine can't? Is it because of the different versions?
No, versions would not have anything to do with it. The code was just wrong. In order to use that function the way it was, you would need to use
[T,Y]=ode45(@(t,x)differential(x,t), [0,20], [i j m]);
Erin Sausage
Erin Sausage 2021년 2월 21일
I see. I'm so greatful for your reply!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Number games에 대해 자세히 알아보기

질문:

2021년 2월 20일

댓글:

2021년 2월 21일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by