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Finding a row with a certain value and the next nth rows after that

조회 수: 14(최근 30일)
Me Me
Me Me 18 Feb 2021
댓글: Me Me 21 Feb 2021
Hi
I would like to find a row with a specific value and the next nth rows after that.
0.8147 0.0975 0.1576 0.1419 0.6557
0.9058 0.2785 0.9706 0.4218 0.0357
0.1270 0.5469 0.9572 0.9157 5
0.9134 0.9575 0.4854 0.7922 0.9340
0.6324 0.9649 0.8003 0.9595 0.6787
0.9134 0.9575 0.4854 0.7922 5
0.6324 0.9649 0.8003 0.9595 0.6787
0.6324 0.9649 0.8003 0.9595 0.6787
So in the above example, i would like to find the last column == 5 and then the next two rows and extract those.
I know how to index and find column ==5 , but not how to find the next two rows.
thanks
  댓글 수: 4
Me Me
Me Me 21 Feb 2021
Okay, Thanks for the help! and sorry for not being clear.
Matt J's answers was what i was looking for excatly :D

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Matt J
Matt J 18 Feb 2021
편집: Matt J 18 Feb 2021
Here's an approach that uses logical indexing only:
A=[ 0.9058 0.2785 0.9706 0.4218 0.0357
0.1270 0.5469 0.9572 0.9157 5
0.9134 0.9575 0.4854 0.7922 0.9340
0.6324 0.9649 0.8003 0.9595 0.6787
0 1 2 3 0.4
0 1 2 3 0.4
0.9134 0.9575 0.4854 0.7922 5
0.6324 0.9649 0.8003 0.9595 0.6787
0.6324 0.9649 0.8003 0.9595 0.6787
0 1 2 3 0.4];
idx = movmax(A(:,end)==5,[2,0]);
A(idx,:)
ans = 6×5
0.1270 0.5469 0.9572 0.9157 5.0000 0.9134 0.9575 0.4854 0.7922 0.9340 0.6324 0.9649 0.8003 0.9595 0.6787 0.9134 0.9575 0.4854 0.7922 5.0000 0.6324 0.9649 0.8003 0.9595 0.6787 0.6324 0.9649 0.8003 0.9595 0.6787

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