Repeat each page of 3d matrix 24 times
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So as part of a script I have:
totmelt(:,:,day)=daymelt2;
Daymelt2 is a 2d matrix, and day is the day of the year (1:365). As it stands I get a 3d matrix with 365 in the 3rd dimension, or 365 pages. But I need the output for each day to be repeated 24times in consecutive pages. So the first 24 pages are the first daymelt2 matrix, the next 24 the the second daymelt2 matrix.
Is there a way I can do this? Without post-processing by extracting every single page and using repmat.
Thank you
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Walter Roberson
2013년 4월 29일
So you want the output to be size(daymelt2,1) x size(daymelt2,2) x 365 x 24 ? Or size(daymelt2,1) x size(daymelt2,2) x (365*24) ?
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Jan
2013년 4월 29일
Perhaps you want:
totmelt = repmat(daymelt2, 1, 1, 24*365);
Or:
totmelt = zeros(M, N, 24, 365); % With matchin M and N
...
totmelt(:, :, :, day) = repmat(daymelt2, 1, 1, 24);
...
totmelt = reshape(totmelt, M, N, 24*365);
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Bård Skaflestad
2013년 4월 29일
As you only need to repeat each page a fixed (and equal) number of times, you can also do something like this:
totmelt = % construct as normal
p = reshape(repmat(1:365, [24, 1]), [], 1);
totmelt = totmelt(:,:,p);
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