# Convert matrix to cell knowing the number of components to have in each cell

조회 수: 2(최근 30일)
Alejandro Fernández 2021년 2월 2일
댓글: Alejandro Fernández 2021년 2월 2일
Hi, does anyone know how I could go from the data matrix to cell A knowing that, in this case:
idx = [2;4;3];
data = rand(9,2);
data =
0.7922 0.3922
0.9595 0.6555
0.6557 0.1712
0.0357 0.7060
0.8491 0.0318
0.9340 0.2769
0.6787 0.0462
0.7577 0.0971
0.7431 0.8235
- The first component of A will be the idx(1) 2 first elements of data.
- The second component of A will be the idx(2) next 4 elements of the array data
- The third component of A will be the next idx(3) 3 elements of the array data
In this case:
A{1} = [0.7922,0.3922;0.9595,0.6555];
A{2} = [0.6557,0.1712;0.0357,0.7060;0.8491,0.0318;0.9340,0.2769];
A{3} = [0.6787,0.0462;0.7577,0.0971;0.7431,0.8235];
##### 댓글 수: 1표시숨기기 없음
Alejandro Fernández 2021년 2월 2일
Another option to do it (which I wouldn't know either) would be, for example, to make a matrix that, based on idx that creates as many ones as elements indicated by idx(1), as many twos as elements indicated by idx(2),... as many x's as elements indicated by idx(end), in this case:
idx = [2;4;3];
B = [1;1;2;2;2;2;3;3;3];
Then a loop could be made so that the different elements could be separated in the corresponding cells.
It's just an idea since, as I said, I wouldn't know how to solve it that way either.

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### 채택된 답변

Stephen Cobeldick 2021년 2월 2일
편집: Stephen Cobeldick 2021년 2월 2일
idx = [2;4;3];
data = [
0.7922 0.3922
0.9595 0.6555
0.6557 0.1712
0.0357 0.7060
0.8491 0.0318
0.9340 0.2769
0.6787 0.0462
0.7577 0.0971
0.7431 0.8235];
A = mat2cell(data,idx,2)
A = 3x1 cell array
{2×2 double} {4×2 double} {3×2 double}
A{:}
ans = 2×2
0.7922 0.3922 0.9595 0.6555
ans = 4×2
0.6557 0.1712 0.0357 0.7060 0.8491 0.0318 0.9340 0.2769
ans = 3×2
0.6787 0.0462 0.7577 0.0971 0.7431 0.8235
##### 댓글 수: 1표시숨기기 없음
Alejandro Fernández 2021년 2월 2일
Wow, amazing! That's easier than any of the ideas I could have come up with, thank you a million times over!

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R2020b

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